Thursday, May 14, 2015

Day 23: Faradays Law and Lenzs Law

  There are two wires which have same current, then we drew the magnetic field and find the magnetic force of them. We know the equation B=u/4pi*Idl/a^2 so we could figure out a new equation F=u/2pia*I_0*I_1*L.

  This experiment shows when the switch is close and the wires were charge, the wires will get closer than not charged.

  We predict there were forces made the wires get closer, but we were wrong, the alternating current made the wires get closer instead of force.

  There is the magnetic field vs. time graph.



  We calculated the magnetic flux. For the first one, the flux is 0 because A and B are parallel. For the second one, the flux is Bab because A and B are perpendicular.


  We started to do the experiment about the magnetic field in a loop.

These are the data we collected in our experiment.

  When the magnet enter or leave the loop, the dash board will change. But when the magnet stay in the loop, it did not change.


  These are the four factors we found can affect the dash board.

  We put a aluminum loop into the equipment, it can suspend.



  If the loop is cut, it can not suspend.

  We drew the forces and magnetic field on the equipment.

  We put a magnet into a magnetic tube, it will drop slower than in a non-magnetic tube.

  First, we drew two graphs of B and E. Then we find the E that the moving magnet created.


Conclusion:
  In the beginning of the class, professor gave us two wires which have same current. We found out the equation F=u/2pia*I_0*I_1*L by using another equation B=u/4pi*Idl/a^2. Then we did an experiment to understand alternating current made the wires get closer instead of forces. Next, professor showed us a very interesting experiment, metal ring will suspend on the equipment but the cut ring can not. And finally, we found the equation -wNpiR^2Bocos(wt).

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